3^x^2=9^x+1/27^x

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Solution for 3^x^2=9^x+1/27^x equation: 



3^x^2=9^x+1/27^x

We move all terms to the left:

3^x^2-(9^x+1/27^x)=0



Domain of the equation: 27^x)!=0

x!=0/1

x!=0

x∈R



We get rid of parentheses

3^x^2-9^x-1/27^x=0

We multiply all the terms by the denominator


3^x^2*27^x-9^x*27^x-1=0

Wy multiply elements

81x^2-243x^2-1=0

We add all the numbers together, and all the variables

-162x^2-1=0

a = -162; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·(-162)·(-1)
Δ = -648
Delta is less than zero, so there is no solution for the equation

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